Can't Buy or Sell

What is greater than gold but cannot be bought. it can never be sold and can earn if its sought. though it can be broken, it can still be fixed. for by birth it can't start nor by death it is ended.what am i?




Similar Riddles

Can you find the missing number in the third row?
35 20 14
27 12 18
5 2 ?

Asked by Neha on 26 Jun 2023


When is the top of a mountain similar to a savings account?

Asked by Neha on 18 Aug 2025

Your mother’s brother’s only brother-in-law is asleep on your couch. Who is asleep on your couch?

Asked by Neha on 14 Mar 2022


Suppose you are a girl candidate and sitting in an interview. Suddenly the interviewer asks you, 'What if one morning you wake up and find out that you are pregnant?

How will you reply to such a question?

Asked by Neha on 29 Apr 2023

John can fit six large chocolate boxes or nine small chocolate boxes into a carton. How many cartons will he require to put sixty-six chocolate boxes into?

Asked by Neha on 25 May 2024

Find three whole, positive numbers that have the same answer when multiplied together as when added together.

Asked by Neha on 01 Jan 2021


The first two letters signify a male, the first three letters signify a female, the first four letters signify a great, while the entire world signifies a great woman. What is the word?

Asked by Neha on 18 Mar 2025

Which word is least like the others? Third, fourth, fifth, sixth, seventh, eighth, ninth?

Asked by Neha on 28 Aug 2025

Find a 9-digit number, which you will gradually round off starting with units, then tenth, hundred etc., until you get to the last numeral, which you do not round off. The rounding alternates (up, down, up ...). After rounding off 8 times, the final number is 500000000. The original number is commensurable by 6 and 7, all the numbers from 1 to 9 are used, and after rounding four times the sum of the not rounded numerals equals 24.

Asked by Neha on 01 Sep 2021


Three cars are driving on a track that forms a perfect circle and is wide enough that multiple cars can pass anytime. The car that is leading in the race right now is driving at 55 MPH and the car that is trailing at the last is going at 45 MPH. The car that is in the middle is somewhere between these two speeds.
Right now, you can assume that there is a distance of x miles between the leading car and the middle car and x miles between the middle car and the last car and also, x is not equal to 0 or 1.
The cars maintain their speed till the leading car catches up with the last car and then every car stops. In this scenario, do you think of any point when the distance between any two pairs will again be x miles i.e. the pairs will be x distance apart at the same time ?

Asked by Neha on 08 May 2021

Hot Articles

Amazing Facts

Out of the Box

The phrase “thinking outside the box” was popularised from the solution to a topographical puzzle involving 9 dots in a box shape.