I am thinking of a five-digit number such that:
The first and last digits are the same, their submission is an even number and multiplication is an odd number and is equal to the fourth number. Subtract five from it and we obtain the second number. Then divide into exact halves and we get the 3rd number.
* When we multiply three numbers, we will get the prime numbers.
* The difference between the second and the first number is equal to the third and second.