Logic Thinking

I am thinking of a five-digit number such that:
The first and last digits are the same, their submission is an even number and multiplication is an odd number and is equal to the fourth number. Subtract five from it and we obtain the second number. Then divide into exact halves and we get the 3rd number.

What number I am thinking of?




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I have thought of a number that is made up by using all the ten digits just once. Here are a few clues for you to guess my number:

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First two digits are divisible by 2.
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First four digits are divisible by 4.
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First six digits are divisible by 6.
First seven digits are divisible by 7.
First eight digits are divisible by 8.
First nine digits are divisible by 9.
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