If a shopkeeper can only place the weights on one side of the common balance. For example, if he has weights 1 and 3 then he can measure 1, 3 and 4 only. Now the question is how many minimum weights and names of the weights you will need to measure all weights from 1 to 1000? This is a fairly simple problem and very easy to prove also.

Imagine you are in a room with no windows or doors. How will you get out?

A blonde put eyeliner on her head. Why?

What is full of holes but still holds water?

I am the one who remains awake when you sleep. But I need to rest when you awake. Who Am I?

I am weightless, but you can see me. Put me in a bucket, and I'll make it lighter. What am I?

A woman lives in a Tall building thirty-six floors high and served by several elevators which stop at each floor going up and down. Each morning she leaves her apartment and goes to one of the elevators. Whichever one she takes is three times more likely to be going up than down. Why?

A network of 20 x 10 squares is given to you.

Can you calculate how many unique squares and rectangles can be formed combining two or more individual squares ?

Can you find the hidden animal in the picture below?

In two decks of cards, what is the least amount of cards you must take to be *guaranteed* at least one four-of-a-kind?