Shopkeeper's Weights

If a shopkeeper can only place the weights on one side of the common balance. For example, if he has weights 1 and 3 then he can measure 1, 3 and 4 only. Now the question is how many minimum weights and names of the weights you will need to measure all weights from 1 to 1000? This is a fairly simple problem and very easy to prove also.




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We have arranged an array of numbers below. What you have to do is use any kind of mathematical symbol you know excluding any symbol that contains a number like cube root. You can use any amount of symbols but you have to come up with a valid equation for all of them.

0 0 0 = 6
1 1 1 = 6
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4 4 4 = 6
5 5 5 = 6
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If nine thousand, nine hundred nine dollars is written as $9,909,
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Now add 1000 one more time.
Now add 30.
Now add 1000 one more time.
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