Shopkeeper's Weights

If a shopkeeper can only place the weights on one side of the common balance. For example, if he has weights 1 and 3 then he can measure 1, 3 and 4 only. Now the question is how many minimum weights and names of the weights you will need to measure all weights from 1 to 1000? This is a fairly simple problem and very easy to prove also.




Similar Riddles

In order to complete the racing competition, the Mexico racetrack has to submit its top and the most famous three horses to win the competition. Due to an electrical storm, all the records are cleared and no one knows which horse holds the record. They all look identical and it becomes even more difficult to differentiate the horses. There are 25 horses in the Mexico racetrack. But there can be only five horses at a time on the track. What will the least number of races that can be conducted to find out the three fastest horses?

Horse Race in Mexico

Asked by Neha on 24 Mar 2021


What number comes next in this sequence:
7 8 5 5 3 4 4 _

Asked by Neha on 06 Aug 2024

Write the next letter in this sequence.
O, T, T, F, F, S, S, E, __
**Hint: It is a Number Series Puzzle

Asked by Neha on 16 Dec 2025


You have two buckets - one holds exactly 5 gallons and the other 3 gallons. How can you measure 4 gallons of water into the 5 gallon bucket?

(Assume you have an unlimited supply of water and that there are no measurement markings of any kind on the buckets.)

Asked by Neha on 26 Apr 2022

You are provided with a grid (as shown in the picture). Can you fill the squares with numbers 1-8 in a manner that none of the two consecutive numbers are placed next to each other in any direction (vertically, horizontally or diagonally?)

Fill The Grid

Asked by Neha on 22 Sep 2025

Can you identify the famous TV character from the rebus below?

Uncover TV character

Asked by Neha on 22 Nov 2023


What is the four-digit number in which the first digit is one-third the second, the third is the sum of the first two, and the last is three times the second?

Asked by Neha on 15 Sep 2025

John's five friends Rachel, Jacob, Phoebe, Joey and Chandler live on the same road.

Rachel lives in the house: A, Jacob lives in the house: B, Phoebe lives in the house: C, Joey lives in the house:D, Chandler lives in the house: E

Mathematically
B*C*D = 1260
B + C + D = 2E
2A = E

The road numbers run from 2 to 222.

Can you tell me the house number of each of John's friends?

Asked by Neha on 10 Sep 2024

If,
29 - 1 = 30
9 - 1 = 10
14 - 1 = 15

Based on similar logic, Can you prove that the below algebraic equation is true?
11 - 1 = 10 ?

Asked by Neha on 04 Jan 2025


They do not possess flesh or feathers or scales or bone
But still, they are blessed with fingers and thumbs of their own.

Asked by Neha on 08 Nov 2023

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