If a shopkeeper can only place the weights on one side of the common balance. For example, if he has weights 1 and 3 then he can measure 1, 3 and 4 only. Now the question is how many minimum weights and names of the weights you will need to measure all weights from 1 to 1000? This is a fairly simple problem and very easy to prove also.

The following alphametic has only one solution. Can you find it?
ENLIST + SILENT + LISTEN = ANAGRAM

PS: You may start the number from 0.

What does below chemistry rebus means?

Two batsman each on 94 runs. Seven runs needed to win in last 3 balls. Both make 100*. How?

Intelligence Agency need to break the vault but the problem is that they are not able to break the vault.

On the vault, a text is written as:

31 11 33 33 43 45
21 25
31 24 11 31 51 41

To Break the code Intelligence Agency brings a mathematician named Joseph.
Minutes later he deciphers the code.

Whats the code?

What does this simple rebus mean?

Yesterday I fell from 30 feet high ladder but I don't get hurt. Why?

What is the next number in this series?

4,12,84,3612....

Count the number of triangles in the given picture.

In 1990, a person is 15 years old. In 1995, that same person is 10 years old. How can this be?