Join the Joint

Can you solve the below algebraic mathematical equation?

(J+O+I+N+T)3 = JOINT




Similar Riddles

A man wants to cross the pit of fire which is 25 feet in length and he has 2 planks(fire resistant) 19 feet in length. How can he cross the pit of fire alive?

Asked by Neha on 02 Oct 2025


What is full of holes but still holds water?

Full of holes riddle

Asked by Neha on 26 Apr 2021

Can you solve this amazing hard number series problem?
7, 8, 10, 12, 16, 18 ?

Asked by Neha on 18 Apr 2024


What has 88 keys?

Asked by Neha on 09 Jul 2025

A tourist visits a small town for his research. While in the town, he decides to get a haircut. Since the town is quite small, there are only two barbers in the town � one on the North Street and one on the South Street. The barbershop on the North Street is a mess and the barber has a weird and pathetic haircut. While the barbershop at the South Street is pretty tidy and the barber as well has an impressive haircut.

Which barbershop will the tourist visit for his haircut and why?

Famous Barber Haircut Riddle

Asked by Neha on 23 Jul 2024

A boy was at a carnival and went to a booth where a man said to the boy, "If I write your exact weight on this piece of paper then you have to give me $50, but if I cannot, I will pay you $50." The boy looked around and saw no scale so he agrees, thinking no matter what the carny writes he'll just say he weighs more or less. In the end the boy ended up paying the man $50. How did the man win the bet?

Asked by Neha on 25 Mar 2022


Why did the Girl throw the butter out of the window?

Asked by Neha on 19 Aug 2024

In the Mexico City area, there are two Houses H1 and H2. Both H1 and H2 have two children each.
In House H1, The boy plays for Mexico Youth academy and the other child plays baseball.
In House H2, The boy Plays soccer for his school in Mexico and they recently have a newborn.

Can you prove that the probability of House-H1 having a girl child is more than that of House-H2?

Asked by Neha on 06 Jun 2024

our enemy challenges you to play Russian Roulette with a 6-cylinder pistol (meaning it has room for 6 bullets). He puts 2 bullets into the gun in consecutive slots, and leaves the next four slots blank. He spins the barrel and hands you the gun. You point the gun at yourself and pull the trigger. It doesn't go off. Your enemy tells you that you need to pull the trigger one more time, and that you can choose to either spin the barrel at random, or not, before pulling the trigger again. Spinning the barrel will position the barrel in a random position.

Assuming you'd like to live, should you spin the barrel or not before pulling the trigger again?

Asked by Neha on 04 May 2022


What do you get if you add 2 to 100 four times?

Tricky Maths

Asked by Neha on 24 Jun 2024

Hot Articles

Amazing Facts

Gambling

In Canada, a mathematical puzzle must be solved in order to win the lottery to classify it as a “game of skill” not gambling.